# Provide a 23 pages analysis while answering the following question: Electron and Proton Atomic Energy. Prepare this assignment according to the guidelines found in the APA Style Guide. An abstract is

Provide a 23 pages analysis while answering the following question: Electron and Proton Atomic Energy. Prepare this assignment according to the guidelines found in the APA Style Guide. An abstract is required. The Relationship between B and I for a wire-carrying current is electromagnetic interaction due to associating elementary particles. Direct RelationshipRelationship between B and R for a wire-carrying current Inverse RelationshipOhm’s law states that the current through a conductor between two points is directly proportional to the potential difference across the two points. I=V/RIn Ohm’s law, I and Rare inversely proportional to each other = TrueIn Ohm’s law, V and Rare directly proportional to each other= TrueA typical galvanometer deflects full scale (the maximum current that you can pass through it) to a draft of 0.010A, and it has a resistance of 50ohms. How can it be converted into a:5A ammeter?V = 0.010*50 = 0.5 VRs =&nbsp. &nbsp.0.5 /4.99 = 0.1002 Ω.&nbsp. By connecting a shunt resistor of 0.1002 Ω in parallel.20V voltmeter?Rt = 20 / 0.010 = 2000 Ω. By connecting a resistor of 1950 Ω in series.50V voltmeter?Rt = 50 / 0.01 = 5000 Ω. By connecting a resistor of 4950 Ω in series.&nbsp.Exit QuestionsWhat is the unit of a magnetic field? B Teslas ( T)What is the company of the magnetic flux? ƟB Webers (Wb)As given by Ampere’s law, the magnetic field increases the distance of the point from the wire.Is there a magnetic field outside of a solenoid? No, outside the solenoid, the area is also fragile due to this cancellation effect. For a solenoid which is long compared to its diameter, the site is very close to zero.What is the force’s direction (up or down) on an electron moving along the positive x-axis and entering a magnetic field perpendicular to the chalkboard (going inside)? UpA galvanometer is used to measure current. TrueA voltmeter has a high internal resistance. TrueAn ammeter has a low internal resistance. TrueAn ammeter is used in parallel in an electrical circuit. False it will cause a short circuitA voltmeter is used in series in an electrical circuit. True&nbsp.&nbsp.&nbsp.&nbsp.&nbsp.&nbsp.&nbsp.&nbsp.&nbsp.&nbsp.&nbsp.&nbsp.&nbsp.&nbsp.&nbsp.&nbsp.&nbsp.&nbsp.&nbsp.&nbsp.&nbsp.&nbsp.&nbsp.&nbsp.&nbsp.&nbsp.&nbsp.&nbsp.&nbsp.&nbsp.&nbsp.&nbsp.&nbsp.&nbsp.&nbsp.&nbsp.&nbsp.&nbsp.&nbsp.&nbsp.&nbsp.&nbsp.&nbsp.&nbsp.&nbsp.&nbsp.&nbsp.&nbsp.&nbsp.&nbsp.&nbsp.&nbsp.&nbsp.&nbsp.&nbsp.&nbsp.&nbsp.&nbsp.&nbsp.&nbsp.&nbsp.&nbsp.&nbsp.&nbsp.&nbsp.&nbsp.&nbsp.&nbsp.&nbsp.&nbsp.&nbsp.&nbsp.&nbsp.&nbsp.&nbsp.&nbsp.&nbsp.&nbsp.&nbsp.&nbsp.&nbsp.&nbsp.&nbsp.&nbsp.&nbsp.&nbsp.&nbsp.&nbsp.&nbsp.&nbsp.&nbsp.&nbsp.&nbsp.&nbsp.&nbsp.&nbsp.&nbsp.Practice Home WorkA typical galvanometer has resistance of 60ohms and it can detect full scale for a voltage of 120mV across its terminals. How can it be made into a 4A ammeter?L = 0.12 / 60 = 0.002 ARs&nbsp.&nbsp. &nbsp.&nbsp.= 0.12 / 3.998 = 0.030015 Ω.&nbsp. By connecting a shunt resistor of 0.030015 Ω in parallel&nbsp.A typical galvanometer deflects full scale of (the maximum current that you can pass through it) to a draft of 0.015A, and it has a resistance of 40Ohms.

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